Hilbert series of exterior algebras
modulo two quadrics
Caius Folkerts
Abstract. We determine the Hilbert series of an exterior algebra over modulo
two general quadratic forms in every dimension by identifying its graded pieces
with Plücker sections on the common isotropic Grassmannians. The same geometric
calculation gives every nonnegative Plücker twist and identifies these Hilbert
functions with those of explicit Richardson varieties. In odd dimension, a
degeneration realizes this correspondence and yields monomial bases and a toric
degeneration of the Plücker ring. We also determine the rational cohomology
and Chow rings in this case, presenting them as complete intersections in the
tautological Chern classes.
1. Introduction
Two alternating forms define both a quotient of the exterior algebra and a family of
common isotropic Grassmannians. We show that the graded pieces of the quotient are the
Plücker sections of these varieties, so their geometry determines the Hilbert series and
explains its combinatorial form. The calculation proves the formula conjectured by Crispin
Quiñonez, Lundqvist and Nenashev [5], who expressed it by walks in a strip and
established it as a coefficientwise upper bound.
Let be a complex vector space of dimension . For , put , and let count walks of length
from to , with steps , staying in .
Theorem 1.1.For general ,
where
The quotient vanishes above degree .
Binomial coefficients outside their ordinary range are zero, and a determinant of size
zero is one. Boij and Lundqvist [4] have also determined the exterior Hilbert series for
even .
The formula follows from a uniform calculation on the common isotropic Grassmannians of
and . For , let
This is the zero scheme of a section of , where is the tautological bundle. For ,
the forms and , with , are the linear Plücker equations for common isotropy.
A cohomology gap in the Koszul resolution shows that restriction of Plücker
sections is surjective with precisely these relations. Hence the degree- exterior
quotient is the space of Plücker sections of . The same calculation determines
all higher Plücker twists. Write and . When , define the interval of -subsets
ordered componentwise.
Theorem 1.2.Suppose and is a nonempty regular zero scheme. For every ,
This Hilbert function counts length-multichains in . The Plücker section ring is
generated in degree one, is Cohen–Macaulay and Gorenstein, and has -invariant . For , its
ideal inside the Grassmannian coordinate ring is generated by
If is normal, this embedding is projectively normal. A general pair has a smooth
nonempty zero scheme of dimension in this range, and has no common isotropic -plane
when .
The class of in -theory is the square of a staircase Schubert class, and hence the class
of the Richardson variety for . Standard monomials on that interval then give the
determinant above. Section 2 carries out this calculation.
In odd dimension the comparison is realized by a degeneration, and the exterior
quotient itself has an explicit basis. For , a general pencil can be written, after changing
basis and the two generators, as
Theorem 1.3.For the pencil (2), the degree-exterior quotient has basis
For , the Plücker ring of has a flat weight degeneration to the Richardson ring
for , and then to its Hibi ring. It has a quadratic Gröbner basis in the good Plücker
coordinates and is Koszul.
The odd-dimensional geometry also determines the topology of . A regular Borel action
gives the Betti numbers, and an explicit integration pairing presents and as
complete intersections in tautological Chern classes, with Hilbert series . A dense
vector-bundle chart proves rationality (Section 4). Returning to the exterior
algebra, the monomial basis refines its Hilbert function by the two halves of
the pencil, and the perfect exterior pairing recovers its two-generator Koszul
homology.
The colored-edge estimate behind the cohomology gap continues to apply to several
alternating forms and gives an exact range of comparison with Plücker sections.
The explicit straightening rules, on the other hand, expose the characteristic
dependence; their denominators give a range in which the same bases survive, while
Frobenius supplies new Koszul cycles and additional quotient classes in larger
dimensions.
2. The Koszul complex and a staircase class
The Koszul complex relates the exterior quotient to Plücker sections. A cohomology gap
makes that comparison exact; a staircase identity in -theory then computes the section
dimensions. The case is immediate, so assume . Write , , and let have dimension two. Set
Lemma 2.1.If and , then for some ,
Proof.A Schur constituent of has . Put . The first block of its Bott sequence, read
in reverse, is
the other block is . These are strictly increasing. For nonzero cohomology each
is negative or at least . If exactly are negative, Bott’s theorem gives and ; see [12,
Corollary 4.1.9].
A weight of the exterior representation selects distinct edges from two copies of
the complete graph on vertices. Count the incidences on the first vertices. Each
selected edge contributes at most one, except for an edge entirely inside these vertices,
which contributes one more. There are at most such internal edges. The highest
weight is an actual weight, so
The evaluation of pairs of alternating forms onto is surjective. Its incidence variety is
therefore a smooth vector bundle over , of dimension
Properness and generic smoothness show that a general zero scheme is smooth of the
expected dimension or empty, and is empty if .
For a regular or nowhere-zero section, the Koszul complex resolves or zero. After
twisting by , its terms are in position . In its cohomology spectral sequence, an entry has
total degree . Lemma 2.1 puts every entry with in total degree at most . An incoming
differential to would start in total degree , so only the ordinary Koszul map
can contribute. There are also no entries of positive total degree. Consequently,
Here , and the Koszul map is wedge multiplication by the two forms. The
same argument gives for every ; for it also makes restriction of Plücker sections
surjective.
2.1. The staircase factorization. The vanishing just proved lets us recover section
dimensions from Euler characteristics. We therefore seek the -class of . The Euler class of a
single alternating form turns out to be the class of a staircase Schubert variety. Let . If
are the formal line-bundle roots of and , the Grassmannian Grothendieck formula [10,
Theorem 7.3] is
For , set and factor from row . The remaining determinant is Vandermonde. The
identity
cancels the denominator and row factors, giving
The Schubert varieties for in opposite flags meet in the Richardson variety . They have
no higher Tor; apply the homological Kleiman–Bertini theorem [9] to a general translate;
opposite flags form one orbit of the Borel group preserving the first Schubert variety.
Consequently
The last identity is the Koszul resolution. It also proves nonemptiness for a general
section in the stated range; the Richardson class has Euler characteristic one, whereas an
empty Koszul zero scheme would have class zero.
2.2. Intervals, multichains and determinants. We recall an elementary form of the
interval standard-monomial theorem [8].
Lemma 2.2.For -subsets , the ideal
is prime. Its degree-quotient has basis with , and has Krull dimension .
Proof.Take an matrix with independent entries in positions and zero elsewhere,
and send to its maximal minor. A nonzero matching can be uncrossed; if rows use
columns , then is also allowed in row and in row , because both interval endpoints
increase with the row. Repeating these exchanges gives the diagonal matching. Thus
a nonzero minor must have , and every forbidden minor vanishes.
Give entry weight . Uncrossing a pair raises its weight by , so the diagonal is the
unique greatest-weight term of every allowed minor. Products indexed by multichains
have distinct diagonal monomials; each row records the sorted list of indices and
recovers the chain.
Plücker straightening spans the quotient by these standard products, and the
preceding independence embeds it in the polynomial ring of matrix entries. Thus
it is a domain. If , the interval has maximal strict chains of elements, obtained
by increasing coordinates from right to left. Counting multichains by their strict
supports gives a polynomial in of degree , proving the dimension. □
Richardson varieties have no higher cohomology in nonnegative Plücker twists [8,
Theorem 5.0.6]. The class identity and the preceding vanishing therefore identify the
Hilbert function of with the multichain count. Put and
The interval is the lattice of ideals of the cell poset of . Its length- multichains count
plane partitions of this shape with entries in . Kreweras’s determinant, in the form of [6,
Proposition 2.2], is
Transposing and complementing the lower binomial entries gives (1).
For , the ideal of is the image of . Since
the Cartan-product map from is onto; its irreducible target has highest weight , and
the product of highest-weight sections is nonzero. Thus the ideal is generated in degree
one, as claimed. The complete section ring of a normal variety is integrally closed, which
proves the projective-normality assertion; it applies in particular to the general smooth
zero scheme.
Taking leading coefficients of the multichain determinant gives
where a negative factorial contributes zero. This is the normalized volume of the order
polytope of . For , the cell poset is a fence and the degree is the Euler secant
number ; the Hessenberg determinant has generating function after division by
.
2.3. Duality and the negative twists. Adjunction gives . To prove Cohen–Macaulayness,
it remains to treat . Write , with . For a nonzero Schur cohomology term, let be the
number of negative Bott entries and . The weight argument gives , also when
.
To obtain the opposite bound, use . Exterior duality replaces degree by , and Serre
duality on the Grassmannian replaces twist by . The complementary constituent is
with crossed Bott entries. The total cohomological degree changes from to . Applying
the same weight bound to this dual term gives
The two bounds differ by . Thus every Koszul term is acyclic in this window. Serre
duality and the nonnegative-twist result now give vanishing of all intermediate cohomology
in every twist. The coordinate ring is the complete section ring, so it is Cohen–Macaulay,
with canonical module its shift by . This proves the Gorenstein assertion of Theorem 1.2.
If , the Hilbert function is identically one, so is a reduced point and the assertion is
immediate.
2.4. The exterior formula. The determinant in (1) is unchanged by transposition and
equals the determinant in Theorem 1.1. To identify it with walks, put
Expanding the upper Hessenberg determinant along its first row gives . For the
adjacency matrix of the path on , the tridiagonal recurrence and corner cofactor give
Thus counts walks of length .
For and , a general zero scheme is empty, so (4) gives vanishing. In degree ,
multiplication of a nonzero coefficient term of by its complementary monomial gives the
top exterior line. The case is immediate. Intersecting the finitely many open conditions
proves Theorem 1.1 in all degrees simultaneously.
3. The odd pencil and its degenerations
For the odd pencil, the Hilbert-function comparison becomes a straightening
procedure. A local inverse removes every monomial outside the interval ; primality
of the interval ring then shows that no further relations occur. Assume . The
canonical-form theorem [5, Theorem 3] puts a general pencil in the form (2). Call good if
Failure of a lower or upper inequality is called left or right failure.
3.1. An inverse on a prefix. To straighten a left-failing monomial, we first divide its
initial segment by the restriction of to that segment. Set ; these elements commute and
square to zero, so the required division becomes an inclusion-map calculation on
subsets.
Lemma 3.1.For a squarefree monomial of degree in , there is an explicit of
degree in the same variables with
Proof.Write , where contains its singleton variables. Let be the pairs not occupied
by a singleton and put . Then . After the singleton factors are fixed, multiplication by
sends -subsets to their -element extensions. Symmetry under permutations preserving
suggests looking for an inverse of the form
For an -subset , put . Removing one of its elements in contributes ; removing
one of its other elements contributes . Thus the required coefficient equations are
Starting with and solving backwards gives
Singleton pairs vanish on multiplication, and complete pairs have even degree, so
no extra signs occur. □
For instance, the first nontrivial inverse is
Prescribe costs on the path edges by
Choose integers with , and put . We take largest -weight as initial weight.
Lemma 3.2.Every left-failing monomial is the unique greatest-weight term of an
element of , and every right-failing monomial is such a term of an element of , for
this single weight.
Proof.For a left failure, start at height one, moving down at selected indices and up
otherwise. Its first exit below zero is at position , with selected variables in that prefix.
Write , with in the prefix. Then
Every other nonzero term introduces a pair . Its cost exceeds the sum of all prefix-pair
costs, so its total -cost increases and its -weight decreases. Reflection interchanges the
matchings and makes the even-edge costs increasing powers of two. It gives the
right-failure assertion. □
3.2. Primality forces equality.Let and
Give weight . Plücker relations are homogeneous for the original vertex multigrading,
hence for this weight. Lemma 3.2 gives
By Lemma 2.2, the latter quotient is a domain of dimension , so this containment gives
an upper bound of for . For the reverse bound, on a Grassmannian chart is defined by the
pairings of its basis vectors with . It is nonempty because the odd-indexed span is
common isotropic. The height theorem therefore gives . Initial ideals preserve dimension,
so both bounds are equalities. A proper further quotient of the finite-type domain
would lower dimension. There can be no additional initial relation, and hence
This is the required Richardson degeneration. Its degree-one basis gives the good
exterior monomials; its full standard basis lifts to the actual products of good Plücker
coordinates on . The rules (5) and their reflections strictly decrease weight and give
unique exterior normal forms.
The path bijection is particularly direct; put down-steps at the indices of
and add a fixed up-step at each end. The good inequalities are exactly the two
walls of the strip. At there is one good monomial, ; above that degree every
monomial has a left failure and the triangular relations span the whole exterior
degree.
3.3. Toric and quadratic degenerations. Embed the Richardson ring into the
band-matrix ring of Lemma 2.2. A diagonal term order gives the good minor initial
monomial
Distinct standard products have distinct leading monomials, so the good minors form a
SAGBI basis. The initial algebra has presentation
Indeed, these relations sort every product into a chain, whose diagonal monomial
determines it uniquely.
For termination, put and give weight . Replacing an incomparable pair by its meet
and join increases the separation of the two ranks without changing their sum, and strictly
lowers this weight. Thus the displayed quadratics are a Gröbner basis with initial ideal
.
The SAGBI step is realized by weights on the finitely many quadratic straightening
relations; their greatest diagonal terms give precisely the meet-and-join binomials.
Equality of standard-monomial Hilbert functions gives equality of the initial ideals.
Combining these weights with (6) at separated scales gives an initial ideal generated by
forbidden variables and these squarefree quadratics. Eliminating the forbidden
variables proves Theorem 1.3; the quadratic Gröbner criterion gives Koszulness [11,
Theorem 5.3].
4. Cohomology and rationality in odd dimension
The canonical odd pencil has a regular Borel action whose tangent weights determine the
Betti numbers. Its integration pairing then recovers the ring structure, while projection
onto one half of the pencil supplies a rational chart.
Throughout this section, . Write and , with bases and , so that
The canonical pair represents the general orbit, so is smooth. Put
Let and let be formal Chern roots. In half the cohomological grading, and . In the
integration pairing, the Grassmannian factor combines with the Euler factor of the
two isotropy conditions to give . Its annihilators come in two families; complete
homogeneous polynomials in these squares, and their first variations under . Define
These are symmetric in the and thus polynomials in the .
Theorem 4.1.Evaluation in the tautological Chern classes gives
The relations form a homogeneous regular sequence. The same presentation gives
, with . Moreover,
and is rational.
4.1. A regular Borel action. For , define
This is one Jordan block. On basis pairs,
Define and . Then , so and define a Borel action, with
It preserves . A single Jordan block has a unique invariant subspace of each dimension,
so the unipotent subgroup fixes only
Thus is a smooth regular Borel variety in the sense of Brion–Carrell [3].
Write an attracting coordinate of weight as having positive weight . At , the
Grassmannian tangent space is , so these weights are . The differential of the two
tautological sections gives the normal weights
They equal the ambient tail with . After reflection about , this is the elementary
multiset identity
The remaining tangent weights are therefore
Brion–Carrell’s zero-scheme description [3, Proposition 2 and (15)] gives one coordinate
of degree and one equation of degree for each weight . Hence
The torus has isolated fixed points. Its Białynicki–Birula decomposition [1, 2] is a
filtrable affine-cell decomposition; consequently integral cohomology is torsion-free and
even, and the cycle map from Chow groups is an isomorphism. The case is a
point.
4.2. The integration pairing. To determine the ring, we compute its integration
pairing on tautological classes. The candidate relations annihilate this pairing, and their
complete-intersection Hilbert series agrees with the Betti numbers just obtained. This will
prove both generation and the relations. Put and, for , let . The Grassmannian coefficient
formula and the Euler class give
For completeness, the Grassmannian coefficient formula follows by evaluating on
Schur functions of top degree; only the rectangle contributes, with coefficient
.
Let average over the independent sign changes of the , and put . Then
Lemma 4.2.For and , one has .
Proof.Put . Partial fractions give
If , the numerator exponent is at least , and divides . Thus , proving the even
case.
For , let . Write , since each surviving exponent of is positive and even.
Differentiate the partial-fraction formula. In
multiplication by gives a polynomial divisible by ; in the first term restores the
lost power; in the second . Therefore the required coefficient vanishes in the odd case
as well. □
4.3. A recurrence for the relations. It remains to show that the first annihilators
already have the required complete-intersection size. Both parity families come from one
Chern polynomial, which gives a recurrence of length . Define
and
With , logarithmic differentiation gives . Its coefficient of is
The leading coefficient is for even and for odd .
At a common zero of , recurrence (7) forces every later to vanish. Then is a
polynomial, and forces . The common zero is therefore the origin. The relations form a
regular sequence in , and
is Artinian Gorenstein of socle degree and Hilbert series .
By Lemma 4.2, factors through . It is nonzero, since . The perfect pairings of imply
that on has rank . This pairing factors through tautological evaluation , so
The endpoints agree by the Betti formula, so every is onto. Now let lie in the relation
ideal. It pairs to zero with every polynomial of complementary degree; surjectivity in that
degree and Poincaré duality imply . Conversely, if , then for every complementary , and
the perfect pairing of forces into the relation ideal. This proves both tautological
generation and the precise kernel. The affine-cell cycle isomorphism gives the Chow
assertion.
The first relations are
For the presentation becomes . For it is , and for it is .
4.4. A dense vector-bundle chart. On the open set , projection to writes as the
graph of for . Both forms vanish on and on , so graph isotropy contains only the cross
terms, linear in . This gives the bundle map
on . The full-space map is an isomorphism. Indeed, writing and setting , its kernel
equations are
They give and ; iteration reaches a zero boundary. Both spaces have dimension
.
Every pair of alternating forms on extends to , so every fiber of is onto. Its kernel is a
vector bundle of rank . The corresponding open of is its total space, of dimension . It is
dense by the prime degeneration (6). A vector bundle over a rational Grassmannian is
rational, completing Theorem 4.1.
5. The exterior quotient and its homology
The good-monomial basis retains the two gradings of the odd pencil, so the geometric
calculation also refines the exterior Hilbert series. The perfect pairing in the ambient
exterior algebra converts the Hilbert function into all the Betti polynomials for the
two-generator action.
5.1. Bigraded dimensions. For the odd pencil, give bidegree and bidegree . Both
relations have bidegree . Let . For , put and define
Proposition 5.1.The bigraded Hilbert function is
Proof.Use the path order , which gives the canonical pencil up to interchanging
its generators and changing a sign. In the good-monomial path, pair the first fixed
up-step with the step, then pair the steps; leave the last fixed up-step unpaired.
Halving the heights gives a walk on , of length , from to . An up-step has weight , a
down-step , a loop at zero , and a loop above zero either or . Its tridiagonal transfer
matrix has , and the corner cofactor is . The required coefficient is therefore . □
There is a compatible action; for its standard module , identify the -span with when
and with zero when , and the -span with . The pencil is multiplication by the two basis
vectors of , and the torus weights are
Corollary 5.2.If , then
Proof.Write the selected -indices as , and the complement of the selected -indices as
. The good inequalities say . They correspond to weakly increasing lists in of length
The original torus weight is twice the sum minus . This is the character of
the stated symmetric power, with weights reversed; characters are invariant under
reversal and determine the representation. □
5.2. Koszulness and the quadratic dual. The Plücker ring in Theorem 1.3 and the
exterior quotient have different homological behavior.
Proposition 5.3.For two general quadrics, is Koszul exactly when . For , its
quadratic dual is , where is two-step nilpotent with and . Hence
Proof.The quadratic dual of an exterior quotient is the enveloping algebra of the
ordinary graded Lie algebra generated by with relation space annihilating in ; see [7,
Section 10]. The dual of is the kernel of
For , Theorem 1.1 gives , so this map is injective. Thus , and Jacobi induction
gives thereafter. PBW gives the series. Koszulness would force , impossible in degrees
above .
For , the series is . The reciprocal of begins
contradicting the nonnegative coefficients required by the Koszul identity. For ,
the generic ideal can be made an exterior quadratic monomial ideal; in dimension
four it is , and in dimension three the path pencil gives . These have quadratic PBW
presentations. □
5.3. The two-generator Koszul homology. For arbitrary , put
Let act on by , , with .
Proposition 5.4.The graded Betti polynomials of over are
There are no later terms.
Proof.These are the Hilbert series of the Koszul homology on multiplication by .
The zeroth is and the second is . The perfect exterior pairing identifies with , giving
. The Euler characteristic gives . The polynomial ring has global dimension two. □
For the two-step Lie algebra with , its Chevalley–Eilenberg complex is with , . Assign
internal weights one to and two to the . Koszul position and internal weight have
cohomological degree , so
Theorem 1.1 therefore determines the full graded Betti sequence for a general pair in
either parity.
6. More alternating forms
The cohomology gap also gives an exactness range for more than two forms. The staircase
class is special to a pair, but the colored-edge bound on Schur weights still controls the
Koszul complex. Let have dimension and let define a section of on . Assume its Koszul
complex is exact, as for a regular zero scheme or a nowhere-zero section. Put
For nonempty regular , adjunction gives .
Theorem 6.1.If , the degree-exterior Koszul complex is exact before its final
quotient, and
Moreover .
Proof.For a Schur constituent of , the colored-edge count gives
For twist , a nonzero cohomology term with negative Bott entries has and,
writing ,
The complementary partition with parts , paired by Serre duality at twist , has crossed
entries and total degree . Combining the two inequalities gives the necessary condition
At , the left side is concave in , with positive endpoint values and on . Thus every
positive cohomology group of every Koszul term vanishes.
In degree zero Bott requires . The constituent is , with multiplicity ; permutations of
the two-form blocks act symmetrically on their exterior product, leaving the alternating
type on . Hence the global-section complex has terms and is exactly the exterior Koszul
complex. Acyclicity of its sheaf terms gives the assertion and the displayed Euler
characteristic. □
Proposition 6.2.If , then and . If and , then
If , then . In all these cases is nonempty.
Proof.At , condition (8) is . For , only the constant term survives. For , only are
possible. The second case forces and , giving the top Koszul term , up to a constant
line. The spectral sequence therefore has just the entries at and . Their total degrees
are , and no differential connects them when . This proves the assertions, including
nonemptiness. □
For three general alternating forms on , the common isotropic Grassmannian of
four-planes has and . Generic smoothness, adjunction, and Proposition 6.2 show that it is
a K3 surface. Theorem 6.1 gives
so its polarization has genus and degree . Its nonzero shows why the full
cohomology of such zero schemes cannot always be generated by tautological Chern
classes.
7. Positive characteristic
The integer denominators in the local inverse determine a range in which straightening
survives in positive characteristic. In larger dimensions, Frobenius supplies new Koszul
cycles that force extra quotient classes. Let now be algebraically closed of characteristic ,
and retain the explicit odd path pencil (2) in .
Theorem 7.1.For and , the good monomials form a basis of the degree-exterior
quotient, and the corresponding Plücker ring has the Richardson initial ideal (6). In
particular, the full characteristic-zero Hilbert series holds whenever .
Proof.The denominators in Lemma 3.1 are , with , and have no prime factor above
. All local inverses therefore exist. The weights, the prime interval ideal, and the
dimension argument apply over .
If , this covers all degrees through . The unique top monomial is , which every
kills. Wedge with the product of all except the one paired with ; only that term
survives, showing that also kills the top class. Thus every higher quotient degree
vanishes. The inequality is exactly . □
The argument is integral. Put and give the successive path edges independent
invertible coefficients . Over
the good monomials form a free basis of the full exterior quotient. A diagonal change of
generators removes the edge coefficients by solving successively along the path. The local
rules span, top-degree annihilation gives the ceiling, and independence follows over the
fraction field. The basis consequently survives arbitrary base change from this
ring.
Theorem 7.2.For every prime and odd , the canonical pair satisfies
Proof.Since commuting square-zero pair monomials satisfy , the kernel of
contains the Koszul vectors and the two vectors , .
Multiplication by is injective on . Decompose by the singleton states of its disjoint
pairs and by its unpaired variable. Every remaining block is the Boolean inclusion
map from -subsets to -subsets of an -set, with and ; the latter follows from . On
any -subset the central map is invertible by Lemma 3.1, whose denominator primes
are at most . Restrict a putative kernel vector to the -subsets of this smaller set. Its
image is still zero, since an -subset contained there receives contributions only from
its own -subsets. Hence all restricted coefficients vanish. Every -subset lies in one of
these smaller sets, proving injectivity. The ordinary Koszul vectors therefore span a
subspace of dimension .
Choose pairwise nonconsecutive -pairs and project all other variables to zero.
Then becomes zero and becomes times the retained product, which is nonzero.
Thus a relation forces . The reflected projection does the same for , so the two
Frobenius vectors are independent modulo the Koszul image. Therefore
For , the two-wall reflection formula reduces to
Indeed, with and , the reflection sum is ; only contribute. Their sum is , equal
to the displayed formula by . Set . □
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